(81)^-4/((729)^(2-x))=9^(4-x)

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Solution for (81)^-4/((729)^(2-x))=9^(4-x) equation: 



(81)^-4/((729)^(2-x))=9^(4-x)

We move all terms to the left:

(81)^-4/((729)^(2-x))-(9^(4-x))=0



Domain of the equation: (729^(2-x))!=0

x∈R



We add all the numbers together, and all the variables

-4/(729^(-1x+2))-(9^(-1x+4))+81^=0

We add all the numbers together, and all the variables

-4/(729^(-1x+2))-(9^(-1x+4))=0

We multiply all the terms by the denominator


-((9^(-1x+4)))*(729^(-1x+2))-4=0



We calculate terms in parentheses: -((9^(-1x+4)))*(729^(-1x+2)), so:

(9^(-1x+4)))*(729^(-1x+2)



We calculate terms in parentheses: +(9^(-1x+4)))*(729^(-1x+2), so:

9^(-1x+4)))*(729^(-1x+2

We add all the numbers together, and all the variables

-1x+9^(-1x+4)))*(729^(+2

Back to the equation:

+(-1x+9^(-1x+4)))*(729^(+2)



We add all the numbers together, and all the variables

(-1x+9^(-1x+4)))*(729^2

Back to the equation:

-((-1x+9^(-1x+4)))*(729^2)



We move all terms containing x to the left, all other terms to the right

-((-1x+9^(-1x+4)))*729^2=4

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